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3 married couples have bought 6 seats in the same row for a talent show. In how many different ways can they be seated if all men sit together to the right of all women?1. 362. 403. 324. 44 |
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Answer» Correct Answer - Option 1 : 36 Given: 3 married couples have bought 6 seats in the same row for a talent show. Formula used: n! = n × (n – 1) × (n – 2) ……………………….3 × 2 × 1 Calculation: The guys all sit first, but they have to take up 3 spaces. Assuming we're dealing with male-female married couples here The men have 3! ways of sitting, as do the women Total= ⇒ 3! × 3! ⇒ (3!)2 ⇒ (6)2 ⇒ 36 ∴Different ways can they be seated if all men sit together to the right of all women is 36. |
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