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3. If4tan A = 3, evaluate: (1tsinALEH S... 2> {(1+cosA) (1- cosA) |
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Answer» Given tanA= 3/4(1+sinA)(1-sinA)/(1+cosA)(1-cosA)= (1- sinA^2)/(1-cosA^2) Using sinA^2 + cosA^2 = 1 = cosA^2 /sinA^2= cotA^2 As tanA = 3/4 then cotA = 4/3 = (4/3)^2= 16/9 = 1.7 ans |
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