1.

3. If the zeroes of the quadratic polynomialp(x) = 3x2 + (2k - 1)x - 5 are equal in magnitude butopposite in sign then find the value of k.

Answer»

let zeroes be a or -athen put in equ.3a^2+(2k-1)a-5=3a^2-(2k-1)a-5(2k-1)a-5=-(2k-1)a-52(2k-1)a=0(4k-2)a=0a≠04K-2=04k=2k=1/2 ansif u satisfied with the ans then like or cmmt ✌️



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