Saved Bookmarks
| 1. |
3. If \tan N=\frac{\operatorname{stan} \alpha}{1+(1-n) \tan ^{2} \alpha} \text { then } \tan (\alpha-\beta)=A)(1+n) \tan \alpha B)(1-n) \tan \alpha C)-(1+n) \tan \alpha D)-(1-n) \tan \alpha |
| Answer» | |