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3: If A (-9,0), B(-1,0) are two points. If P is apoint such that PA : PB = 3:1, then thelocus of P is(a) x² + y2 = 9 (b) x² + y2 + 9 = 0(c) x² - y2 = 9 (d) x² - y2 + 9 = 0 |
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