3. (i) The amount with Aarthi is 80 more than thatwith Bhargavi. Chand

1.	3. (i) The amount with Aarthi is 80 more than thatwith Bhargavi. Chandini has 50 less than theamount with Bhargavi. Divyani has 120 morethan the sum of the amounts with Bhargavi andChandini. The money with them, when pooledtogether, is in denominations of 10 and 520 onlyand they together have a total of 500. What isthe least number of 10 notes they can have?(A) 1 (B) 2 (C) 3(D) 4CARS
Answer» ANSWER: The minimum no. of 10 notes required is 1. Step-by-step explanation: LET the amount with Aarti be A, Bhargavi be B and Chandani be C. According to Question, A = B + 80 --------------------(1) C = B - 50 ---------------------(2) D = 120 + B + C ⇒ D = 120 + 2B - 50 ⇒ D = 2B + 70 --------------------(3) A+B+C+D = 500 ⇒ B+80 + B + B-50 + 2B + 70 = 500 ⇒ 5B = 500 - 100 ⇒ 5B = 400 ⇒ B = 80 ⇒ A = 160 ⇒ C = 30 ⇒ D = 230 Denominations are of --- 5, 10, 20 So, the amount can be divided as --- (11x20) + (10x1) So, the minimum no. of 10 notes required is 1. Hope this helps.....

3. (i) The amount with Aarthi is 80 more than thatwith Bhargavi. Chandini has 50 less than theamount with Bhargavi. Divyani has 120 morethan the sum of the amounts with Bhargavi andChandini. The money with them, when pooledtogether, is in denominations of 10 and 520 onlyand they together have a total of 500. What isthe least number of 10 notes they can have?(A) 1 (B) 2 (C) 3(D) 4CARS

Answer»

Step-by-step explanation:

LET the amount with Aarti be A, Bhargavi be B and Chandani be C.

According to Question, A = B + 80 --------------------(1)

C = B - 50 ---------------------(2)

D = 120 + B + C

⇒ D = 120 + 2B - 50

⇒ D = 2B + 70 --------------------(3)

A+B+C+D = 500

⇒ B+80 + B + B-50 + 2B + 70 = 500

⇒ 5B = 500 - 100

⇒ 5B = 400

⇒ B = 80

⇒ A = 160

⇒ C = 30

⇒ D = 230

Denominations are of --- 5, 10, 20

So, the amount can be divided as --- (11x20) + (10x1)

So, the minimum no. of 10 notes required is 1.

Hope this helps.....