3(i) (sin90°+ cos60° + cos45°) X (sin 30° — cos0° + cos 45°)

1.	3(i) (sin90°+ cos60° + cos45°) X (sin 30° — cos0° + cos 45°)
Answer» sin90=1cos60=1/2cos45=1/√2sin30=1/2cos0=1cos45=1/√2Hence put in the equation hence1+1/2+1/√2(1/2-1+1/√2)=(3/2+1/√2)(-1/2+1/√2)=3√2+2/2√2*(-√2+2/√2)=-6+6√2-2√2+4/2=-2+4√2/2=-1+2√2 sin90=1,cos60=1/2,cos45=1/2

Answer»

sin90=1cos60=1/2cos45=1/√2sin30=1/2cos0=1cos45=1/√2Hence put in the equation hence1+1/2+1/√2*(1/2-1+1/√2)=(3/2+1/√2)*(-1/2+1/√2)=3√2+2/2√2*(-√2+2/√2)=-6+6√2-2√2+4/2=-2+4√2/2=-1+2√2

sin90=1,cos60=1/2,cos45=1/2

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3(i) (sin90°+ cos60° + cos45°) X (sin 30° — cos0° + cos 45°)

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