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3 g of H2 reacts with 29 g of O2 to yield water. Which is the limiting reactant? (A) H2 (B) O2 (C) H2O (D) none of there |
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Answer» Correct option: (A) H2 2H2 + O2 → 2H2O Ratio of mole of reactant, H2 : O2 = \(\cfrac{2}{1}\) = 2 Actual amount 3 g of H2 and 29 g of O2. \(\cfrac{3}{2}\) = 1.5 mol of H2 and \(\cfrac{29}{32}\) = 0.91 mol of O2. Ratio of actual moles of H2 : O2 = \(\cfrac{1.5}{0.91}\) = 1.66 Theoretical ratio of moles of H2 : O2 = 2 Actual ratio of moles of H2 : O2 = 1.66 Hence, H2 is limiting reactant and O2 is excess reactant. |
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