Saved Bookmarks
| 1. |
3) For an AP if tn = 4.n=1.0= 4 find a |
|
Answer» Answer: t n
=4n−3 Put n = 1 ∴t 1
=4×1−3 =4−3=1 ∴ FIRST term (t 1
)=1 Put n = 2 ∴t 2
=4×2−3 =8−3=5 ∴ SECOND term (t 2
)=5 |
|