3. Find the sum of the lengths of the bases of a trapezium whose altit

1.	3. Find the sum of the lengths of the bases of a trapezium whose altitude is 11 cm and whose arcais 0.55 m2me.
Answer» Area of trapezium =1/2 (sum of parallel sides) × (perpendicular distance between them) Given, Area = .55 m^2, altitude = 11 cm or .11 mLet sum of the length of bases = n Then we get, .55 = n*.11n = .55/.11 = 5 Therefore, sum of the length of bases = 5 m or 500 cm

3. Find the sum of the lengths of the bases of a trapezium whose altitude is 11 cm and whose arcais 0.55 m2me.

Answer»

Area of trapezium =1/2 (sum of parallel sides) × (perpendicular distance between them)

Given, Area = .55 m^2, altitude = 11 cm or .11 mLet sum of the length of bases = n

Then we get, .55 = n*.11n = .55/.11 = 5

Therefore, sum of the length of bases = 5 m or 500 cm