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(3)) Find the sum of first n odd natural numbers. |
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Answer» Natural odd no:s forms an A.P 1,3,5,7 .... a = 1 , d = 2 Sn = n/2 [ 2a + [n-1]d ] = n/2 [ 2 + 2n - 2 ] = n/2 [ 2n ] = n² Sum of n natural odd no:s = n² Like my answer if you find it useful! |
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