3.Find the smallest number exactly divisible by 12, 20, 24 and 32.

1.	3.Find the smallest number exactly divisible by 12, 20, 24 and 32.
Answer» Smallest number exactly divisible by 12,20,224 and 32 is their LCM. Prime factorisation: 12 =22320 =22524=222332=22222 LCM is given by the product of prime factors, each raised by the highest exponent. As 2 occur maximum 5 times, 3 and 5 occur one time each. LCM =222223*5 =480 Hence, the required smallest number is 480.

Answer»

Smallest number exactly divisible by 12,20,224 and 32 is their LCM.

Prime factorisation:

12 =2*2*320 =2*2*524=2*2*2*332=2*2*2*2*2

LCM is given by the product of prime factors, each raised by the highest exponent. As 2 occur maximum 5 times, 3 and 5 occur one time each.

LCM =2*2*2*2*2*3*5 =480

Hence, the required smallest number is 480.

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