1.

3)Find the simple interest on Rs 1 po1000 for 2 years at 8% perannum*​

Answer»

Given :-

  • Principal ( P ) = RS 1,000  
  • RATE of interest ( r ) R = 8 %  
  • TIME ( T ) = 2 YEARS  

To Find :-

  • Calculate the simple interest ( SI )  

Solution :-

~Here, we’re given the principal , rate of interest, time and we need to find the simple interest. We can easily find the simple interest by putting the values in the FORMULA.  

____________

As we know that ,

\boxed{\sf{ \maltese \;\; SI = \dfrac{ P \times r \times T }{100}}}

Finding the simple interest :-

\sf \dashrightarrow SI = \dfrac{1,000 \times 8 \times 2 }{100}

\sf \dashrightarrow SI = 10 \times 8 \times 2

\boxed{\bf{ \bigstar \;\; Simple\;Interest = Rs. \; 160 }}

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Hence,  

  • The simple interest is of Rs. 160



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