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3. Find the greatest number of six digits which is a perfect square. Find the squareroot of this number. |
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Answer» Let x² be the largest six-digit perfect square. The largest six-digit number is 999,999, sox² ≤ 999,999. You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².(1,000 - 1)² = 999² = 998,001. |
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