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3. Find the dimensions of a rectangle whose perimeter is 28 m and area is 40 sq.m. |
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Answer» Given :-Perimeter of rectangle = 28 2 (l + b ) = 28 l + b = 14 l = 14 - b --- (i) area = 40 l × b = 40 from (i) ( 14 -b ) × b = 40 (14 - b²) = 40 b² - 14b + 40 = 0 After spilliting the zeros you will get... (length) = 10(breadth) = 4 Area of a cube is 25 sq.m. what is its volume |
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