1.

3. Find the dimensions of a rectangle whose perimeter is 28 m and area is 40 sq.m.

Answer»

Given :-Perimeter of rectangle = 28

2 (l + b ) = 28

l + b = 14

l = 14 - b --- (i)

area = 40

l × b = 40

from (i)

( 14 -b ) × b = 40

(14 - b²) = 40

b² - 14b + 40 = 0

After spilliting the zeros you will get...

(length) = 10(breadth) = 4

Area of a cube is 25 sq.m. what is its volume



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