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3. Evaluate:sin2 63+sin2 27°0 cos 17° + cos?7 |
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Answer» We know,cos x = sin (90 - x)sin x = cos (90 - x)sin^2 x + cos^2 x = 1 Then,sin^2 63 + sin^2 27/ cos^2 x 17 + cos^2 73= sin^2 63 + cos^2 (90 - 27)/ sin^2 (90 - 17) + cos^2 73= sin^2 63 + cos^2 63/ sin^2 73 + cos^2 73= 1/1= 1 Therefore its value = 1 |
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