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3. Divide the following by long division meth(a) (6a? - a -5) by (2a +1) |
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Answer» Answer: x2–3x+2=(X−1)(x−2) Let f(x)=x3+ax2−bx+10 REMAINDER Theorem: If an arbitrary function f(x) divided by (x−a) leaves a remainder r, we write, f(a)=r. When r=0,x=a is a ZERO of the polynomial f(x) f(1)=0 ⟹1+a−b+10=0 ⟹a−b=−11……[i] f(2)=0 ⟹8+4a−2b+10=0 ⟹2a−b=−9……[ii] [ii]−[i]⟹a=2 a−b=−11⟹b=a+11=2+11=13 a=2,b=13 |
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