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√3 cosec 20°-sec 20°=4 |
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Answer» √3 cosec 20° - sec 20° = √3/ sin 20° - 1/ cos 20°= √3cos 20° - sin 20°/ sin 20° cos 20° = 4 [√3/2 cos 20° - 1/2 sin 20° / 2 sin 20° cos 20°]= 4 [ sin 60° cos 20° - cos 60° sin 20°/ sin 40°] -- ( 2 sin A cos A = sin 2A) Using identity sin ( A - B ) = sin A cos B - cos A sin B= 4 sin (60° - 20°) / sin 40°= 4 sin 40°/ sin 40°= 4 Required Answer is 4 hit like if you find it useful |
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