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3. Complete the table :Volume of the cuboidLengthHeightBreadth(i)8 m2 m3 m11 m5 m3 m8 m6 m2.5 m(iv)10 m5 m2 m |
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Answer» Step-by-step explanation: (1) length =12 CM breadth =10 cm height =5 cm TSA=2(lb+bh+lh)=2[12×10+10×5+5×12] TSA=2[120+50+60]=2×230 [TSA=460cm 2 ] (2) length =5 cm breadth =3.5 cm height =1.4 cm TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5] TSA=2[17.5+4.90+7.0]=2[29.4] [TSA=58.8cm 2 ] (3) length =2.5 cm breadth =2 m height =2.4 m TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025] TSA=2[0.05+4.8+0.0600]=2[4.91] (4) length =8 m breadth =5 m height =3.5 m TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8] TSA=2[40+17.5+28.0]=2[85.5] [TSA=171.0m 2 ] |
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