3. AD is an altitude of an isosceles ΔABC in which AB = AC. Show that – InterviewSolution

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3. AD is an altitude of an isosceles ΔABC in which AB = AC. Show that AD bisects BC.

Answer»

Given: AD is an altitude of an isosceles triangle ABC in which AB = AC. (ii) AD BISECTS ∠A. ∴ BD = CD | C.P.C.T. ⇒ AD bisects BC.

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