1.

3) A Train starting from rest attains a speed of 12km/HR in 5min Find the acceration and the distance traveled​

Answer»

EXPLANATION:

INITIAL VELOCITY,u=0

final velocity,v=12km/hr

time,t=5 min=5/60 hours

now v=u+at

12=0+a×5/60

12×60/5=a

a=144km/hr2

now

{v}^{2}  -  {u}^{2}  = 2as

12×12-0=2×144×s

1/2=s or s=0.5km



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