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3) A Train starting from rest attains a speed of 12km/HR in 5min Find the acceration and the distance traveled |
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Answer» final velocity,v=12km/hr time,t=5 min=5/60 hours now v=u+at 12=0+a×5/60 12×60/5=a a=144km/hr2 now 12×12-0=2×144×s 1/2=s or s=0.5km |
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