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3. A solution is prepared by dissolving 3.65g of HCl in 500ml of the solution .Calculate the molarity of the solution. Determine the volume of this solution required to prepare250ml of 0.001M solution. |
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Answer» 1)molarity=0.2M2)VOLUME=1.25mlExplanation:1)GIVEN,Volume V=500mlWeight W=3.65gMolecular Mass M=1+35.5=36.5gm/molMolarity S=?Then,W=(SVM)/1000Or,S=W×1000/V×MOr,S=3.65×1000/500×36.5Therefore,Molarity S=0.2M2)LET,S1=0.2M V2=250ml S2=0.001MV1=?Now,V1S1=V2S2or,V1=250×0.001/0.2Therefore,V1=1.25ml. |
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