3-√5/3+2√5= a√5- (19/11)Find a.pls answer honestly or I will rep

1.	3-√5/3+2√5= a√5- (19/11)Find a.pls answer honestly or I will report. Best answer will be marked brainliest.
Answer» ANSWER: =(3-√5)/(3+2√5) =(3-√5)/(3+2√5)×(3-2√5)/(3-2√5) =(3-√5)(3-2√5)/(3+2√5)(3-2√5) =[3(3-2√5)-√5(3-2√5)]/(3²-(2√5)² =(3²-6√5-3√5+2(5))/(9-4(5) =(9-9√5+10)/(9-20) =(19-9√5)/(-11) =–(19-9√5)/ 11 = –(19-9√5)/11 =(-19+9√5)/11 =(9√5-19)/11 =9√5/11 - 19/11 = a√5-19/11 Therefore,a=9/11 If it is (a√5-19)/11 then a=9 But according to question,a√5-19/11 So,answer is 9/11

3-√5/3+2√5= a√5- (19/11)Find a.pls answer honestly or I will report. Best answer will be marked brainliest.

Answer»

=(3-√5)/(3+2√5)

=(3-√5)/(3+2√5)×(3-2√5)/(3-2√5)

=(3-√5)(3-2√5)/(3+2√5)(3-2√5)

=[3(3-2√5)-√5(3-2√5)]/(3²-(2√5)²

=(3²-6√5-3√5+2(5))/(9-4(5)

=(9-9√5+10)/(9-20)

=(19-9√5)/(-11)

=–(19-9√5)/ 11

= –(19-9√5)/11

=(-19+9√5)/11

=(9√5-19)/11

=9√5/11 - 19/11 = a√5-19/11

Therefore,a=9/11

If it is (a√5-19)/11 then a=9

But according to question,a√5-19/11

So,answer is 9/11