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3.(4) 2If nth term of a series is 3 ", then the sum toen the sum to n terms of the series will be(1)를(3n) |
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Answer» nth term of series = 3^nFirst term a1 = 3^1 = 3Second term a2 = 3^2 = 9 Common difference d = 9 - 3 = 6 Sum of n terms of series= n/2[2a1 + (n-1)d]= n/2[2*3 + (n-1)6]= n/2(6 + 6n - 6)= 3n^2 |
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