1.

3(2x+y)=7xy;3(x+3y)=11xy

Answer»

3(2x+y) = 7xy -> 6x+3y = 7xy 3(x+3y) = 11xy -> 3x+9y = 11xy Multiply 2nd equation by 2 and subtract from 1st equation 6x + 3y - 6x - 18y = 7xy - 22xy -15y = -15xy xy - y = 0 x(y-1) = 0 x = 0 or y = 1 x = 0 -> 6*0 + 3y = 0 so y = 0 y = 1 -> 6x + 3 = 7x so x = 3

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