3(2^x+1) — 2^x+2 + 5 = 0 prove

1.	3(2^x+1) — 2^x+2 + 5 = 0 prove
Answer» ANSWER: $3( {2}^{x} + 1) - {2}^{x} + 2 + 5 \\ 0= 3. {2}^{x} + 3 - {2}^{x} + 2 + 5 \\0 = 3. {2}^{x} - {2}^{x} + 10 \\ - 10 = {2}^{x} (3 - 1) \\ - 10 = {2}^{x} (2) \\ - 10 = {2}^{x + 1} \\$

Answer»

$3( {2}^{x} + 1) - {2}^{x} + 2 + 5 \\ 0= 3. {2}^{x} + 3 - {2}^{x} + 2 + 5 \\0 = 3. {2}^{x} - {2}^{x} + 10 \\ - 10 = {2}^{x} (3 - 1) \\ - 10 = {2}^{x} (2) \\ - 10 = {2}^{x + 1} \\$

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3(2^x+1) — 2^x+2 + 5 = 0 prove

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