3. 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel a

1.	3. 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in thisreaction will be:A) 3 molB) 4 molC) 1 mol
Answer» moles of H2 = 10/2 = 5moles of O2 = 64/32 = 2 now , 2H2 + O2 → 2H2O so, molee of H2O , will be twice the moles of O2 , because O2 is limiting reagent so, moles of H2O = 2*2 = 4 mol

3. 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in thisreaction will be:A) 3 molB) 4 molC) 1 mol

Answer»

moles of H2 = 10/2 = 5moles of O2 = 64/32 = 2

now , 2H2 + O2 → 2H2O

so, molee of H2O , will be twice the moles of O2 , because O2 is limiting reagent

so, moles of H2O = 2*2 = 4 mol