3.1 (2x-3)1x²–2x = 0(2x-3)* (27-3then p.q are roots of2 x +x-2=0 3

1.	3.1 (2x-3)1x²–2x = 0(2x-3)* (27-3then p.q are roots of2 x +x-2=0 3 x -3x+2=04) x² + 2x=0
Answer» Multiply the given equation throughout with (2x - 3)² px + q = (2x - 3) + 3px + q = 2x(p - 2)x + q = 0Comparing coeficients of x on both sides,p - 2 = 0 p = 2Comparing constant terms on both sides, q = 0 From the given options find out the quadratic equation whose zeroes are 0 and 2. x² - 2x = 0=> x(x - 2) = 0=> x = 0, x = 2 Thus, p and q are the roots of x² - 2x = 0

3.1 (2x-3)1x²–2x = 0(2x-3)* (27-3then p.q are roots of2 x +x-2=0 3 x -3x+2=04) x² + 2x=0

Answer»

Multiply the given equation throughout with (2x - 3)²

px + q = (2x - 3) + 3px + q = 2x(p - 2)x + q = 0Comparing coeficients of x on both sides,p - 2 = 0 p = 2Comparing constant terms on both sides, q = 0

From the given options find out the quadratic equation whose zeroes are 0 and 2.

x² - 2x = 0=> x(x - 2) = 0=> x = 0, x = 2

Thus, p and q are the roots of x² - 2x = 0