1.

3-0)and sec (B+C-A) 2. find the value of AB18. In an acute angled ABC, utan (and C

Answer»

tan (A+B-C)= tan π/4sec(B+C-A)= π/3A+B-C= π/4B+C-A= π/3adding both2B= 105B= 52.5°



Discussion

No Comment Found