1.

2y²-19y+44 factorise​

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ANSWER:

Factoring 2y2-19y+44

The first term is, 2y2 its coefficient is 2 .

The middle term is, -19y its coefficient is -19 .

The last term, "the constant", is +44

Step-1 : Multiply the coefficient of the first term by the constant 2 • 44 = 88

Step-2 : Find two factors of 88 whose sum EQUALS the coefficient of the middle term, which is -19 .

-88 + -1 = -89

-44 + -2 = -46

-22 + -4 = -26

-11 + -8 = -19 That's it

Step-3 : Rewrite the POLYNOMIAL splitting the middle term using the two factors found in step 2 above, -11 and -8

2y2 - 11y - 8y - 44

Step-4 : Add up the first 2 TERMS, pulling out like factors :

y • (2y-11)

Add up the last 2 terms, pulling out common factors :

4 • (2y-11)

Step-5 : Add up the four terms of step 4 :

(y-4) • (2y-11)

Which is the desired factorization

Step-by-step explanation:

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