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(2xx+3= o EI=2 -+x+3 D] ल5; दिया e Bx=-3,x== |
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Answer» 2(2x-1/x+3)-3(x+3/2x-1)=5or, {2(2x-1)²-3(x+3)²}/(x+3)(2x-1)=5or, {2(4x²-4x+1)-3(x²+6x+9)}/(2x²+6x-x-3)=5or, 8x²-8x+2-3x²-18x-27=5(2x²+5x-3)or, 5x²-26x-25=10x²+25x-15or, 5x²-10x²-26x-25x-25+15=0or, -5x²-51x-10=0or, 5x²+50x+x+10=0or, 5x(x+10)+1(x+10)=0or, (x+10)(5x+1)=0Either, x+10=0or, x=-10Or, 5x+1=0or, 5x=-1or, x=-1/5∴, x=10,-1/5 Like my answer if you find it useful! |
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