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∫2x+5√7−6x−x2dx=A√7−6x−x2+Bsin−1(x+34)+C (where C is a constant of integration), then the value of B−A is equal to |
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Answer» ∫2x+5√7−6x−x2dx=A√7−6x−x2+Bsin−1(x+34)+C (where C is a constant of integration), then the value of B−A is equal to |
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