1.

2x+3y=5. 3x-y=2 by elimination method

Answer»

ANSWER:

x=1,y=1

Step-by-step explanation:

(2x+3y=5)×3

=6x+9y=15 (1st EQ)

(3x-y=2)×2

=6x-2y=4 (2nd eq)

2nd eq -1st eq

6x-2y=4

6x+9y=15

(-) (-)

-11y=-11

y=1

subtitute'y' in 1st eq

6x+9(1)=15

6x+9=15

6x=6

x=1

I hope this answer MAY HELP you



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