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2x+3y=5. 3x-y=2 by elimination method |
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Answer» x=1,y=1 Step-by-step explanation: (2x+3y=5)×3 =6x+9y=15 (1st EQ) (3x-y=2)×2 =6x-2y=4 (2nd eq) 2nd eq -1st eq 6x-2y=4 6x+9y=15 (-) (-) -11y=-11 y=1 subtitute'y' in 1st eq 6x+9(1)=15 6x+9=15 6x=6 x=1 |
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