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(2x-3y+5)(2x-3y-5) |
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Answer» let 2x-3y = a=therefore equation becomes=(a+5)(a-5)=a^2-5a+5a-25=a^2-25 now substitute the values=a^2-25=(2x-3y)^2-25=4x^2-2(2x ×3y)+9y^2-25 |
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