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2x + 3y = 03x + 4y = 5( By substitution method )

Answer» 2x + 3y = 0 ............. \: eq.1\\ 3x + 4y = 5............. \: eq.2
Taking the LCM of 2 and 3 to eliminate x :-

3(2x + 3y = 0)
2(3x +4y = 5)

Or

6x + 9y = 0.......... eq.3
-2(3x+4y =5).... eq.4

Subtracting 4th eq from the 3RD gives :-

y = - 10

Now substituting y in the 1st eq :-

2x + 3(-10) = 0
2x - 30 = 0
x = 30/2
Or x = 15

Therefore, the values of x and y are 15 and - 10 respectively.

P. S. - I just realized it has to be DONE using substitution. Apologies! (You've GOT both the methods, you lucky PAL!)


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