(-2x+1) whole cube =6(x+2)

1.	(-2x+1) whole cube =6(x+2)
Answer» Answer: Step-by-step EXPLANATION: Using identity (a+b)^3 = a^3 + b^3 + 3AB (a+b) = (-2x)^3 + (1)^3 + 3×(-2x)×1 (-2x + 1) = 6(x + 2) = -8x^3 + 1 - 6x(-2x + 1) = 6x + 12 = -8x^3 + 1 + 12x^2 - 6x = 6x + 12 = -8x^3 + 12x^2 - 6x + 1 is not EQUAL to 6x + 12 This is ur answer. ThankQ @RãßhmîVèrmã.

Answer»

Answer:

Step-by-step EXPLANATION:

Using identity (a+b)^3 = a^3 + b^3 + 3AB (a+b)

= (-2x)^3 + (1)^3 + 3×(-2x)×1 (-2x + 1) = 6(x + 2)

= -8x^3 + 1 - 6x(-2x + 1) = 6x + 12

= -8x^3 + 1 + 12x^2 - 6x = 6x + 12

= -8x^3 + 12x^2 - 6x + 1 is not EQUAL to 6x + 12

This is ur answer.

ThankQ

@RãßhmîVèrmã.

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(-2x+1) whole cube =6(x+2)

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