1.

(2x-1)^2 = 0 solve by factorisation method

Answer»

ANSWER:

(2x - 1)^{<klux>2</klux>} = (2x)^{2} - 2 (2x) (1) + 1^{2} (IDENTITY 2)

= 4x^{2} - 4x + 1 = 4x^{2} - 2x - 2x + 1 = 2x (2x -1) -1 (2x - 1) = (2x - 1) (2x - 1) (verification)

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