1.

2tan x15, -बनाsin 2x = 2 sinx cos x =

Answer»

We know, one important identity , sin( A + B) =sinA.cosB + cosA. sinB

let A = x B = x

then, sin( x + x ) = sinx.cosx + cosx .sinx sin2x = 2sinx.cosx.

Now, take RHS =>2tanx / (1+tan^2x) = 2tanx / sec^2x = (2sinx/cosx) / (1/cos^2x) = (2sinx/cosx)(cos^2x/1) = 2sinxcosx = sin(2x) = LHS



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