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2tan 30. ¥ का भाग है1+ tan® 30A) sin 60 (B} cos 60tan 60° (D) sec 60F |
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Answer» tan 30 = 1/√3Then,2tan30/(1+tan^2 30) =2×1/√3/(1+(1/√3)²)=2/√3/(1+1/3) in brackets by taking 3 as lcm we get=2/√3/ (3+1/3)=2/√3 / 4/3=2/√3×3/4=3/2√3 (3 can be written as√3×√3)=√3×√3 / 2√3=√3/2= sin 60 (A) is correct option |
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