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2SO2(g) + O2(g) ⇔ 2SO3(g) How many molecules of oxygen react with 1.2 × 10-2 moles of sulphur dioxide to produce sulphur trioxide? plsss |
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Answer» + O2(g) ⇔ 2SO3(g)How MANY MOLECULES of oxygen react with 1.2 × 10-2 moles of sulphur DIOXIDE to producesulphur trioxide?2 × S + 2 × O = 2×16 +2× 6. = 32+12 =44= 1.2 × 10-² /44= 0.0028 × 10-² |
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