1.

2So the remainder obtained on dividing q(t) by 2t + 1 is 0.Also, a242.+ 422multipleSo, 21 + 1 is a factor of the given polynomial q(t), that is 9(1) is a2t + 1.EXERCISE 2.31. Find the remainder when x3 + 3x2 + 3x + 1 is divided bysin p5+21() x+1(ii) x(iii) x(iv) x +22. Find the remainder when x3 – ax2 + 6x – a is divided by x - a.3. Check whether 7 + 3x is a factor of 3x3 + 7x.4.5 Factorisation of PolynomialsLet us now look at the situation of Example 10 above more closely. It tells us that sincethe remainder, a0, (2t + 1) is a factor of q(t), i.e., q(t) = (2t + 1) g(t)2​

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YES it is a DIFFICULT QUESTION



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