2sinf —3cosf4sinf —9cos0secl = 5—l3 , ereofled =3 e PSS

1.	2sinf —3cosf4sinf —9cos0secl = 5—l3 , ereofled =3 e PSS
Answer» sec theta = 13/5 cos theta = 1/sec theta = 5/13 sin^2 theta = 1- cos^2 theta = 1 - (5/13)^2 = 1 - 25/169 = 169-25 / 169 = 144/169 sin theta = 12/13 Now, put the values in the equation = 2 sin theta - 3 cos theta / 4 sin theta - 9 cos theta = ( 212/13 - 35/13 ) / ( 412/13 - 95/13) = ( 24/13 - 15/13) / ( 48/13 - 45/13) = { (24-15)/13} / { (48-45)/13 } Cancel out that 13. = 9/3 = 3

Answer»

sec theta = 13/5

cos theta = 1/sec theta = 5/13

sin^2 theta = 1- cos^2 theta

= 1 - (5/13)^2 = 1 - 25/169 = 169-25 / 169 = 144/169

sin theta = 12/13

Now, put the values in the equation

= 2 sin theta - 3 cos theta / 4 sin theta - 9 cos theta

= ( 2*12/13 - 3*5/13 ) / ( 4*12/13 - 9*5/13)

= ( 24/13 - 15/13) / ( 48/13 - 45/13)

= { (24-15)/13} / { (48-45)/13 }

Cancel out that 13.

= 9/3

= 3

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