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2sin81/cos9—tan40/cot50 |
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Answer» Answer: 2sin81/cos9 - tan40/cot50 = 2(sin(90-9)/cos9) - TAN(90-50)/cot50 = 2(cos9/cos9) - cot50/cot50 = 2(1) - 1 = 2 - 1 =1 Hope this helps you BUDDY! PLEASE mark this answer as the brainlist answer!! |
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