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2sin²x=3cosx |
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Answer» Ye koi teacher h bhai Typing ke time square kaise likha aapne Given Equation is 2sin²x + 3cosx = 0\xa0⇒ 2(1 - cos²x) + 3cosx = 0\xa0⇒ 2 - 2cos²x + 3cosx = 0\xa0⇒ 2cos²x - 3cosx - 2 = 0\xa0⇒ 2cos²x - 4cosx + cosx - 2 = 0\xa0⇒ 2cosx(cosx - 2) + (cosx - 2) = 0\xa0⇒ (2cosx + 1)(cosx - 2) = 0\xa0⇒ cosx - 1/2, cosx = 2[Not possible]\xa0⇒ cosx = -1/2\xa0⇒ x = 120°,240°\xa0⇒ x = (2π/3) + 2πn, x = (4π/3) + 2πn |
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