2Fe(s) + 32 O2(g)→Fe2O3(s) (△H=−193.4kJ) ......(1) Mg(s) – InterviewSolution

1.	2Fe(s) + 32 O2(g)→Fe2O3(s) (△H=−193.4kJ) ......(1) Mg(s) + 12 O2(g)→MgO(s) (△H=−140.2kJ) ......(2) What is △H of the reaction? 3Mg + Fe2O3→3MgO + 2Fe
Answer» $2 F e (s) + \frac{3}{2} O_{2} (g) \to F e_{2} O_{3} (s) (△ H = - 193.4 k J) . . . . . . (1)$ $M g (s) + \frac{1}{2} O_{2} (g) \to M g O (s) (△ H = - 140.2 k J) . . . . . . (2)$ What is $△$ H of the reaction? $3 M g + F e_{2} O_{3} \to 3 M g O + 2 F e$

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