2BF3(g)+6NaH180 oC−−−−→P(g)+Q(s) Find out maximum number of – InterviewSolution

1.	2BF3(g)+6NaH180 oC−−−−→P(g)+Q(s) Find out maximum number of atom(s) that can lie in a plane of covalent molecule 'P'.
Answer» $2 B F_{3} (g) + 6 N a H 180^{o} C - --- \to P (g) + Q (s)$ Find out maximum number of atom(s) that can lie in a plane of covalent molecule 'P'.

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