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%2B B ) = \sqrt 3 \text and \tan ( A - B ) = \frac 1 \sqrt 3 ; 0 ^ \circ < A %2B B \leq 90 ^ \circ ; A > B , \text find A \text and B |
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Answer» tan(a+b)= tan 60tan(a-b)= tan 30nowA+B= 60---(1)A-B= 30-----(2) adding both 2A= 90A= 45°and B= 15° thank you |
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