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2abax + by = 1; bx + ayat + b |
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Answer» ax+by=1................(i)bx+ay=2ab/a² + b² .......................(ii) ax+by=1 .................. *aa²x + aby = a ....................(iii) bx+ay=2ab/(a² + b²).......................* bb ² x +aby = 2ab² /(a² + b²)..........(iv) subtracting eq (iv) from (iii)a²x + aby = a - [b ² x +aby = 2ab² /(a² + b²)]a²x - b²x + aby - aby = a -2ab² /(a² + b²)(a² - b²)x = [a(a² + b²) - 2ab²]/(a² + b²)(a² - b²)x = [a³ + ab² - 2ab²]/(a² + b²)(a² - b²)x = [a³ - ab²]/(a² + b²)x = [a(a² - b²)] / (a² + b²)(a² - b²)x = a/ (a² + b²) putting x in (i)ax+by=1a [a/ (a² + b²)] +by = 1a²/(a² + b²) + by = 1by = 1 - a²/(a² + b²)by = [a² + b² - a²]/a² + b²by = b²/a² + b²y = b²/(a² + b²)(b)y = b/a² + b² x = a/ (a² + b²)y = b/a² + b² Like my answer if you find it useful! |
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