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(2a – 3b + c )^2please solve this for me |
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Answer» Step-by-step EXPLANATION: We KNOW that, (x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz Therefore, (2a–3b+c)^2=(2a)^2+(–3b)^2+(c)^2+2(2a×–3 b)+2(–3b×c)+2(2a×c) 4a^2+9b^2+c^2+2(-6ab)+2(-3BC)+2(2AC) 4a^2+9b^2+c^2-12ab-6bc+4ac |
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