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29. A conical vessel of radius 6 cm and height 8 cm is completely filled with water. Asphere is lowered into the water and its size is such that it touches the sides it isjust immersed. What fraction of water overflows? |
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Answer» Radius (R) of conical vessel = 6 cm Height (H) of conical vessel = 8 cm volume of conical vessel (Vc) = 1/3πr^2h= 1/3π × 36 × 8= 96πLet the radius of the sphere be r cm. In right ΔPO'R, by Pythagoras theorem: L = √(64 + 36) L = 10 cm Hence sin = O'P / PR = 6/10 = 3/5 In right triangle MRO Sin = OM /OR = r / OR 3/5 = r / (8 - r) ⇒ 24 – 3r = 5r ⇒ 8r = 24 ⇒ r = 3 cm ∴ Volume of sphere (Vs) Now, Volume of the water = Volume of cone (Vc) = 96 π cm3 Clearly, Volume of the water that flows out of cone is same as the volume of the sphere i.e. Vs. ∴ Fraction of the water that flows out Vs/Vc = 36π / 96π = 3/8Vs : Vc = 3 : 8 |
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